T1 Rs I
o-----*---------. .---*---/\/\/\---*-->--o
| C\ /E | |
| ----- '-----. |
| | | |
Uin | | ----- | Uout
| Rb | C/ \E |
'---/\/\/\---*---------' '---'
T2
o--------------------------------------------o
GND GND
All Transistors are NPN types
This circruit is not very complicated. Transistor T1 gets its base current from
Rb. If we assume, that the circruit is not active, because we have no overload
condition, the voltage across Rs is below 0.7V. T2 doesnīt conduct.
If the current rises to about I=0.7V/Rs, the voltage across Rs rises and T2 begins to
conduct. T2 draws the useless base current away from T1 and T1 gets a higher resistance.
The higher it gets, the more T1 blocks the current. Because of the transistorīs
input characteristic this is not a real current source, but limits quite well.
The disadvantages are, that thereīs also a voltage drop across T1 and Rs if the
circruit does not limit and that the UBE voltage of T2, which we assumed with 0.7V
depends on the transistor and drops about 2mV/K.
Rs T1 I
o---*---/\/\/\---. .--------------------*->-o
| C\ /E |
| ----- |
| | |
| Rb | |
*---/\/\/\------* |
| | T2 |
Uin | | -----*------------* Uout
| C\ /E | |
| ----- ----- C1 |
| | ----- |
| R1 | | R2 |
'------/\/\/\------*-------*---/\/\/\---'
o-----------------------------------------------o
GND GND
All Transistors are NPN types
This is another quite useful circruit. It behaves like a fuse.
But unlike a fuse, you can reset it. by disabling and reenabling Uin after eleminating the error.
The behaviour is a little bit tricky. As you can see, T2 monitors the voltage, again.
But the voltage is divided down by R1 and R2 and the monitored voltage is also the whole across
Rs and T1. This is the reason why it acts like a fuse. Think about any load connected to
it and everything is normal. No overload. We have some voltage across Rs, lets say 0.3V and
forward a voltage across T1 of about 0.8V. These 1.1V are divided e.g. by two by R1 and R2.
So we have 0.55V UBE on T2. T2 doesnīt conduct. Now, if the current rises, The voltage drop
arcoss Rs and T1 gets bigger. Once it reaches 1.4V, UBE of T2 is 0.7V. T2 begins to conduct
somewhat. T2 draws some of the base current of T1 (which is supplied by Rb)
away. T1 begins to cut off a bit. Because of that, the voltage drop increases, UBE of T2
gets bigger, it conducts better and T1 cuts off more and more. - The "fuse" is "blown".
Note, that thereīs still some current flowing through R1, R2 and Rb, which gets to the load,
so itīs an aim to keep them high.
The disadvantages are, that thereīs also a voltage drop across T1 and Rs if the
circruit does not limit and that the UBE voltage of T2, which we assumed with 0.7V
drops about 2mV/K. The trip current is determined by the UCE of T1 (and therefore a bit
by Rb), the UBE of T2, by Rs and by R1 and R2. C1 is for oscillation damping. If you make C1
too high, it slows down the circruit, because C1 has to be charged to get UBE of T2 to rise.
On the other hand, you can use C1 to slow down the raction and simulate a slower fuse.
Copyright (C) 2003 by Wiesner Thomas
Last change: June 9th 2003